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How To Determine Loop Load in Process Current Measurements
Process current (4-20 mA) measurements are popular with DATAQ Instruments' customers, and that often leads to some interesting application questions. One of the better ones relates to how many process current instruments can be connected to a single current loop. Customers know that there MUST be a limit, but they're not sure about how to quantify it. This application note will answer that question so you know exactly how far you've pushed your current loop, and how much further you can go before getting into trouble. First, here's a checklist of items that you'll need to determine process current loop load. The indicated variable for each will be used in subsequent equations that mathematically tie all the different elements together.
You're now equipped with everything you need to determine process current loop load. Start by summing all the shunt resistor values, and then multiply by the worst case current (20 mA). This yields the voltage dropped by all the series instruments (Vs). Here's the equation in general form where variable x is the number of shunt resistors:
Next, assemble values for transducer compliance voltage (VT) and loop power supply voltage (VL) and compare as follows:
Equation (2) defines the condition that must exist for the transducer to operate properly. As you add instruments to a process current loop, each drops a voltage in direct proportion to the value of its shunt resistor. The sum of these voltage drops will lower the voltage that the transducer sees, and there is a point where that voltage is lower than the minimum required by the transducer to operate. Let's look at an example: Suppose we have three instruments connected to a process current loop with shunt resistor values of 35, 50, and 250 ohms. Also assume that the minimum transducer compliance voltage (VT) is 12 V, and the loop power supply voltage (VL) is 20 V. First, we'll determine the total voltage dropped by the shunts (VS) using Equation (1):
Next, we'll plug values into Equation (2) and see if we meet its requirements:
Since the difference between the power supply voltage and the sum of shunt voltage drops is greater than the transducer's minimum compliance voltage, this configuration works. If not, then you have the following options:
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